Respuesta :
In this question, you simply have to multiply the decimal value of 71%, which is 0.71, to its initial height until the desired height is sought.
1.5 meters = 150 cm
For a:
[tex] \alpha_{n} = 150*0.71 ^{n-1} [/tex]
This would be the rule for each of the curved path of the ball.
For b.
n=6
[tex]\alpha_{6} = 150*0.71 ^{6-1}[/tex]
[tex] \alpha_{6}=27.06[/tex]
The height of the ball at its sixth path would be 27.06 cm.
1.5 meters = 150 cm
For a:
[tex] \alpha_{n} = 150*0.71 ^{n-1} [/tex]
This would be the rule for each of the curved path of the ball.
For b.
n=6
[tex]\alpha_{6} = 150*0.71 ^{6-1}[/tex]
[tex] \alpha_{6}=27.06[/tex]
The height of the ball at its sixth path would be 27.06 cm.
Answer:
Step-by-step explanation:
The correct answer for this question is A(n) = 0.75 x (1.5)n-1; 35.6 cm (gradpoint)