Question

How many moles of mg(oh)2(aq) would be required to neutralize 3.0 mol hcl(aq)?

Answer 1

The balanced reaction is:

Mg(OH)2 + 2HCl = MgCl2 + 2H2O

We are given the amount of calcium hydroxide for the reaction to use. This will be the starting point for our calculations.

0.30 mol Mg(OH)2 ( 2 mol HCl / 1 mol Mg(OH)2 ) = 0.60 mol HCl

Answer 2

Answer : The number of moles of $Mg(OH)_2$ required to neutralize 3.0 mole of HCl will be, 1.5 moles

Explanation : Given,

Moles of HCl = 3.0 mole

The balanced chemical reaction will be,

$Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O$

From the balanced chemical reaction, we conclude that

As, 2 moles of HCl neutralizes the 1 mole of $Mg(OH)_2$

So, 3.0 moles of HCl neutralizes the $\frac{3.0}{2}=1.5$ moles of $Mg(OH)_2$

Therefore, the number of moles of $Mg(OH)_2$ required to neutralize 3.0 mole of HCl will be, 1.5 moles