Question

Find the distance between points p(8, 2) and q(3, 8) to the nearest tenth.

Answer 1

distance between two points, d, is given by
$d= \sqrt{ ( x_{2} - x_{1}) ^{2} + (y_{2} - y_{1}) ^{2} }$
where: (x1, y1) = (8, 2) and (x2, y2) = (3, 8)
$d= \sqrt{ ( 3 - 8) ^{2} + (8 - 2) ^{2} } \\ d= \sqrt{ (-5)^{2} + 6^{2} } \\ d= \sqrt{25+36} \\ d= \sqrt{61} \\ d=7.8 \ units$
 

Answer 2

Answer:

7.8

Step-by-step explanation:

Given two points P(8,2) and Q(3,8). To find the distance between the two point can be gotten by using the formula for calculating the distance between two points on a line. The formula for calculating the distance between two points is given as;

d =√(x2-x1)²+(y2-y1)²

Where P(x1,y1) = (8,2)

Q(x2,y2) = (3,8)

From the points given, x1=8, y1=2, x2= 3, y2=8

substituting the values into the given formula, we will have;

Q-P = √(3-8)²+(8-2)²

Q-P = √(-5)²+6²

Q-P = √25+36

Q-P = √61

Q-P = 7.81

Q-P = 7.8(to the nearest tenth)