Question

What mass of chlorine gas will react with 92.0 g of sodium?

Answer 1

The balanced chemical reaction is:

2Na + Cl2 = 2NaCl

We are given the amount of sodium to be used for the reaction. This will be the starting point of our calculations.

92.0 g Na ( 1 mol Na / 22.99 g Na ) ( 1 mol Cl2 / 2 mol Na ) ( 70.9 g Cl2 / 1 mol Cl2) = 141.86 g Cl2

Answer 2

Answer: The mass of chlorine gas will be, 284 grams

Explanation : Given,

Mass of sodium = 92 g

Molar mass of sodium = 23 g/mole

Molar mass of chlorine gas = 71 g/mole

First we have to calculate the moles of sodium.

$\text{Moles of Na}=\frac{\text{Mass of Na}}{\text{Molar mass of Na}}=\frac{92g}{23g/mole}=4moles$

Now we have to calculate the moles of chlorine gas.

The balanced chemical reaction will be,

$2Na+Cl_2\rightarrow 2NaCl$

From the balanced chemical reaction, we conclude that

As, 2 moles of Na react with 2 mole of $Cl_2$

So, 4 moles of Na react with $\frac{2}{2}\times 4=4$ moles of $Cl_2$

Now we have to calculate the mass of chlorine gas.

$\text{Mass of }Cl_2=\text{Moles of }Cl_2\times \text{Molar mass of }Cl_2$

$\text{Mass of }Cl_2=4moles\times 71g/mole=284g$

Therefore, the mass of chlorine gas will be, 284 grams