Respuesta :

The balanced chemical reaction will be:

C2H2 + 3/2O2 = 2CO2 +H2O

We are given the amount of C2H2 to be burned. This will be our starting point.

35.0 mol C2H2 ( 2 mol CO2/1 mol C2H2) = 70.0 mol O2

Therefore, the CO2 produced is 70.0 moles.


Answer: The moles of [tex]CO_2[/tex] produced will be 70 moles.

Explanation:

The chemical reaction for the combustion of ethyne follows the equation:

[tex]2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O[/tex]

By Stoichiometry of the reaction:

2 moles of ethyne produces 4 moles of carbon dioxide.

So, 35 moles of ethyne will produce = [tex]\frac{4}{2}\times 35=70moles[/tex] of carbon dioxide.

Hence, the moles of [tex]CO_2[/tex] produced will be 70 moles.