Respuesta :
The balanced chemical reaction will be:
C2H2 + 3/2O2 = 2CO2 +H2O
We are given the amount of C2H2 to be burned. This will be our starting point.
35.0 mol C2H2 ( 2 mol CO2/1 mol C2H2) = 70.0 mol O2
Therefore, the CO2 produced is 70.0 moles.
Answer: The moles of [tex]CO_2[/tex] produced will be 70 moles.
Explanation:
The chemical reaction for the combustion of ethyne follows the equation:
[tex]2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O[/tex]
By Stoichiometry of the reaction:
2 moles of ethyne produces 4 moles of carbon dioxide.
So, 35 moles of ethyne will produce = [tex]\frac{4}{2}\times 35=70moles[/tex] of carbon dioxide.
Hence, the moles of [tex]CO_2[/tex] produced will be 70 moles.