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A cannon ball is fired horizontally with a velocity of 50 metre per sec from the top of a cliff 90m high. After how many seconds will it strike the plain at the foot of the cliff? with what velocity will it strike the ground?​

Respuesta :

First you calculate how long it will take for the object to fall the 90 meters. We'll take Earth's gravity acceleration as 9.8m/s²

Equation:

x = x₀ + v₀ * (t - t₀) + 1/2 * a * (t - t₀)²

x -> Final position in meters

x₀ -> Starting position

v₀ -> Starting velocity

t -> Final time

t₀ -> Starting time

a -> Acceleration

Our case:

x = 0

x₀ = 90m

v₀ = 0m/s

t = ?

t₀ = 0

a = -9.8m/s² (Minus 9.8 because it's on top of a cliff (90m) and it's falling to ground level (0m), so it's substracting)

0 = 90 - 1/2 * 9.8 * (t - 0)²

0 = 90 - 4.9t²

4.9t² = 90

t² = 90/4.9

t = √(18.36) = 4.28 seconds

To calculate the speed, just multiply the seconds it takes to hit the ground by the acceleration of Earth's gravity:

4.28 * 9.8 = 42m/s