Question

Which volume of 0.10m naoh exactly neutralizes 15.0 milliliters of 0.20m hno3?

Answer 1

The balanced chemical reaction is:

HNO3 + NaOH = NaNO3 + H2O

We are given the amount and concentration of the reactants. The values given will be the starting point.

0.20 mol /L HNO3 (.015 L) (1 mol NaOH / 1 mol HNO3) = 0.003 mol NaOH

0.003 mol NaOH / 0.10 mol/ L NaOH = 0.03 L NaOH or 30 mL NaOH

Answer 2

The volume of 0.1 M NaOH needed to neutralize 15 mL of 0.2 M HNO₃ solution is 30 mL

Balanced equation

HNO₃ + NaOH —> NaNO₃ + H₂O

From the balanced equation above,

• The mole ratio of the acid, HNO₃ (nA) = 1
• The mole ratio of the base, NaOH (nB) = 1

How to determine the volume of NaOH

• Concentration of base, NaOH (Cb) = 0.1 M
• Volume of acid, HNO₃ (Va) = 15 mL
• Concentration of acid, HNO₃ (Ca) = 0.2 M
• Volume of base, NaOH (Vb) = ?

CaVa / CbVb = nA / nB

(0.2 × 15) / (0.1 × Vb) = 1

3 / 0.1 × Vb = 1

Cross multiply

0.1 × Vb = 3

Divide both side by 0.1

Vb = 3 / 0.1

Vb = 30 mL

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