The length of a rectangle is 7 feet more than twice the width, and the area of the rectangle is 99 ft.² Find the dimensions of the rectangle
![The length of a rectangle is 7 feet more than twice the width and the area of the rectangle is 99 ft Find the dimensions of the rectangle class=](https://us-static.z-dn.net/files/d7f/b73713c824184f81097f84a72694bdc3.png)
Answer:
Step-by-step explanation:
A = L * W
A = 99
L = 2w + 7
now we sub
99 = (2w + 7)(w)
99 = 2w^2 + 7w
2w^2 + 7w - 99 = 0
(2w - 11)(w + 9) = 0
2w - 11 = 0
2w = 11
w = 11/2
w = 5 1/2 ft (or 5.5 ft) <==== width is 5 1/2 ft)
L = 2w + 7
L = 2(5.5) + 7
L = 11 + 7
L = 18 ft <====== length is 18 ft