A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver's velocity remains constant. What is the work done by the nonconservative force of air resistance, which is the only nonconservative force acting?
A) +2.93 times 10^5 J
B) 0J
C) Answer is not obtainable, because insufficient information about the skydiver's speed is given.
D) -2.93 times 10^5 J

Respuesta :

Answer:

The answer is A

Explanation:

Work done = mgh

where mass, m = 92kg, g= 9.81, height,h= 325m

Therefore,

W= mgh

W=92*9.81*325

W=293319

W=2.93*10>5

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