Question

A device plugged into a wall outlet experiences an alternating current. The RMS current value is 2 A. The peak current is ___.

Answer 1

Answer:

The peak value of current will be 2.828 A.

Explanation:

Given that

Value of RMS current I(rms) = 2 A

Lets take peak current = I(p)

As we know that relationship between RMS and peak current given as

$I(rms)=\dfrac{I(p)}{\sqrt2}$

Now by putting the values in the above equation

$I(rms)=\dfrac{I(p)}{\sqrt2}$

$2\ A=\dfrac{I(p)}{\sqrt2}$

$I(p)=2\sqrt2$

As we know that

$\sqrt{2}=1.414$

Therefore

I(p)=2.828 A

The peak value of current will be 2.828 A.