When a is equals to 5, b will be 27.
Step-by-step explanation:
Given variables are a and b;
The sum of a and b is 24.
a+b = 24 Eqn 1
Their difference is 6.
a-b = 6 Eqn 2
Adding equation 1 and 2
[tex](a+b)+(a-b)=24-6\\a+b+a-b=18\\2a=18[/tex]
Dividing both sides by 2
[tex]\frac{2a}{2}=\frac{18}{2}\\a=9[/tex]
Putting a = 9 in Eqn 1
[tex]9+b=24\\b=24-9\\b=15[/tex]
As a and b are inversely proportional;
[tex]a[/tex]∝[tex]\frac{1}{b}[/tex]
[tex]a=\frac{k}{b}[/tex]
Where k is constant of proportionality.
k = ab
k = 15*9 = 135
Putting a=5
[tex]5*b=135\\5b=135[/tex]
Dividing both sides by 5
[tex]\frac{5b}{5}=\frac{135}{5}\\b=27[/tex]
When a is equals to 5, b will be 27.
Keywords: inverse proportion, multiplication
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