Question

please answer this exponents and powers question

Answer 1

Answer:

(a) 2

Step-by-step explanation:

$(9^2 - 4^3) \times (\dfrac{-3}{17})^2 \times \dfrac{34}{9} =$

$= (81 - 64) \times \dfrac{(-3)^2}{(17)^2} \times \dfrac{34}{9}$

$= 17 \times \dfrac{9}{17 \times 17} \times \dfrac{2 \times 17}{9}$

$= \dfrac{17 \times 9 \times 2 \times 17}{17 \times 17 \times 9}$

$= \dfrac{17 \times 17 \times 9 \times 2}{17 \times 17 \times 9}$

$= 2$

Answer 2

The above answer is correct.....