Respuesta :
Answer:
Anaphase I - 2n = 6
Metaphase I - 2n = 6
Anaphase II- n = 3
Metaphase II- 2n = 6
Explanation:
In a meiosis cell division there are two cycle of division Meiosis I and Meiosis II. The genetic material duplicates during the S phase of meiosis I and hence at metaphase I the number of chromosomes will be 2n i.e 6. The number of chromosomes in Anaphase I is equal to the number of chromosomes in metaphase I since the chromatids remain attached during the anaphase stage. During metaphase II, the cell separates and hence the number of chromosomes at this stage is equal to n i.e 3 while at anaphase II the number of chromosomes is equal to 6
Answer:
Explanation:
During metaphase I homologous chromosomes become aligned along the equator of a cell. Therefore a cell contains 6 duplicated chromosomes. It also contains 6 duplicated chromosomes at Anaphase I.
Meiosis II which is a resuctional division process results in the halfing of the chromosome number.
Therefore, Metaphase II and Anaphase II has 3 chromosomes.