Answer:
h = 48.077 ft
Explanation:
given,
distance between two observer = 300 ft
angle of elevation to top pole = 16° and 20°
height of the flagpole = ?
now,
Let h be the height of the flagpole
Let x be the distance of the pole
[tex]tan 16^0 = \dfrac{h}{x}[/tex]
[tex]x =\dfrac{h}{tan 16^0}[/tex]
now,
again applying
[tex]tan 20^0 = \dfrac{h}{300-x}[/tex]
[tex]300-x=\dfrac{h}{tan 20^0}[/tex]
[tex]300-3.49 h=2.75 h[/tex]
[tex]6.24h = 300[/tex]
h = 48.077 ft