Question

Radio astronomers detect electromagnetic radiation at 50.0 MHz from an interstellar gas cloud. They suspect this radiation is emitted by electrons spiraling in a magnetic field. What is the magnetic field strength inside the gas cloud?

Answer 1

Answer:

0.00178 T

Explanation:

f = Frequency = 50 MHz

m = Mass of electron = $9.11\times 10^{-31}\ kg$

q = Charge of electron = $1.6\times 10^{-19}\ C$

In circular motion the magnetic field is given by

$B=\dfrac{2\pi fm}{q}\\\Rightarrow B=\dfrac{2\pi 50\times 10^6\times 9.11\times 10^{-31}}{1.6\times 10^{-19}}\\\Rightarrow B=0.00178\ T$

The magnetic field strength inside the gas cloud is 0.00178 T

Answer 2

The magnetic field strength inside the interstellar gas cloud is 1.79 × 10⁻³T.

Given the data in the question;

Frequency; $f = 50.0 MHz = 5.0 * 10^7 Hz$

To get the magnetic field strength inside the gas cloud, we use the expression for the frequency of the cyclotron:

$f = \frac{qB}{2\pi m}$

Where;

• f is the frequency

• q is the charge of the electron ( $1.602*10^{-19} C$ )

• m is the mass of electron ( $9.11*10^{-31} kg$ )

• B is the Electric Field

Let make "B" the subject of the formula

$B = \frac{2\pi fm }{q}$

We substitute our values into the equation

$B= \frac{2*\pi * ( 5.0*10^7Hz)* (9.11*10^{-31}kg)}{1.602*10^{-19C}}\\\\B = \frac{2.86199*10^{-22}Kg.Hz}{1.602*10^{-19C}}\\\\B = 1.79 * 10^{-3}T$

Therefore, the magnetic field strength inside the interstellar gas cloud is 1.79 × 10⁻³T.

Learn more: https://brainly.com/question/14952984