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The overall reaction 2Co3+(aq) + 2Cl-(aq) ? 2Co2+(aq) + Cl2(g) has the standard cell voltage Eocell= 0.46 V.

Given that Cl2(g) + 2e-? 2Cl-(aq), Eo = 1.36 V,

calculate the standard reduction potential for the following the half reaction at 25oC:

Co3+ + e-? Co2+

1.82 V
-0.90 V
0.90 V
-1.82 V

Respuesta :

Answer: Option (a) is the correct answer.

Explanation:

The given overall reaction will be as follows.

      [tex]2Co^{3+}(aq) + 2Cl^{-}(aq) \rightarrow 2Co^{2+}(aq) + Cl_{2}(g)[/tex]

It is given that standard potential of the cell is 0.46 V.

Hence, the oxidation and reduction half reactions of the cell are as follows.

Reduction-half reaction: [tex]Cl_{2}(g) + 2e^{-} \rightarrow 2Cl^{-}(aq)[/tex],    [tex]E^{o} = 1.36 V[/tex]

Oxidation-half reaction: [tex]2Co^{3+}(aq) \rightarrow 2Co^{2+}(aq)[/tex],  [tex]E^{o} = ?[/tex]

Now, expression of [tex]E^{o}_{cell}[/tex] of this reaction is as follows.

        [tex]E^{o}_{cell} = E^{o}_{Co^{3+}/Co^{2+}} - E^{o}_{Cl_{2}/Cl^{-}}[/tex]

Putting the given values into the above formula as follows.

     0.46 V =  [tex]E^{o}_{Co^{3+}/Co^{2+}}[/tex] - 1.36 V

  [tex]E^{o}_{Co^{3+}/Co^{2+}}[/tex] = 1.82 V

Thus, we can conclude that standard potential of the given half cell is 1.82 V.

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