The intensity of the waves from a point source at a distance d from the source is I. At what distance from the sources is the intensity equal to 2I

Respuesta :

Answer:[tex]d'=\frac{d}{\sqrt{2}}[/tex]

Explanation:

Intensity of the waves from a point source can be given by Power divided by surface area.

For P Power source and at a distance d from source Intensity is given by

[tex]I=\frac{P}{\pi\cdot d^2}--------1[/tex]

when intensity is 2I then it is at a distance of let say d'

[tex]2I=\frac{P}{\pi\cdot d'^2}--------2[/tex]

Divide 1 and 2 we get

[tex]\frac{I}{2I}=\frac{P}{\pi\cdot d^2}\times \frac{\pi\cdot d'^2}{P}[/tex]

[tex]\frac{1}{2}=(\frac{d'}{d})^2[/tex]

[tex]\frac{d'}{d}=\frac{1}{\sqrt{2}}[/tex]

[tex]d'=\frac{d}{\sqrt{2}}[/tex]

     

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