Question

What is the equation of the line that passes through the point (-6, -3) and is perpendicular to the line y = -0.4x

Answer 1

Answer:

y = 2.5 x + 12

Step-by-step explanation:

y = -0.4x

y = mx + b      m = - 0.4 = - 4/10

slope (m') of line perpendicular to y=-0.4x    m' = 10/4 = 2.5

y' = 2.5 x' + b'      b' = (-3) - (2.5 x (-6)) = (-3) + 15 = 12

equation: y' = 2.5 x' + 12