Answer
given,
constant acceleration of car when it slows = 5 m/s²
Assume the initial speed of car = 29 m/s
distance taken by car before stopping = ?
using equation of motion
v² = u² + 2 a s
v is the final speed = 0 m/s
u is the initial seed of car = 29 m/s
a = - 5 m/s²
now,
0² = 29² - 2 x 5 x s
10 s = 841
[tex]s = \dfrac{841}{10}[/tex]
s = 84.1 m
hence, if initial velocity is equal to 29 m/s then car will stop at 84.1 m