Question

A forward-biased silicon diode is connected to a 6.0-V battery. Also in the circuit are three 220 Ω resistors connected in series. The diode potential difference in the circuit is 0.70 V. What is the current?

Answer 1

Answer:

Current in the circuit will be 0.024 A

Explanation:

We have given battery voltage v = 6 volt

Resistance R = 220 ohm

Diode potential $v_d$ = 0.7 volt

So voltage across the resistance = 6 - 0.7 = 5.3 volt

Current is given by $current=\frac{voltage}{reistance}=\frac{5.3}{220}=0.024A$

So current in the circuit will be 0.024 A