Respuesta :
Answer: 10 dimes
the pile with the least number of dimes have 10 dimes
Step-by-step explanation:
Given;
Total number of dimes of the stack = 45
Ratio of division into piles = 1/6 : 1/3 : 1/4
Multiplying the ratio through by 12.
12(1/6 : 1/3 : 1/4) = 2 : 4 : 3
The least number of dimes in a pile(Nl) is that of the least ratio; which is 2
Ni = 2/(2+4+3) × 45
Ni = 2/9 × 45
Ni = 10 dimes
Therefore, the pile with the least number of dimes have 10 dimes
Answer:
10 dimes
Step-by-step explanation:
First we get rid of the fractions. Multiply everything by 12. So the new ratio is 2:4:3. Then add 2+3+4 which is 9. So 45/9=5, and 5*2 (which is the smallest number in the ratio) is 10. So the answer is 10 dimes.
