Answer:
The probability that the first defective item occurred in the first 12 inspection is 0.3012
step-by-step explanation:
This is a binomial distribution question;
P= 0.15 (prob of success)
q=1-p, q= 1- 0.15= 0.85
n= 12 x= 1
Using the binomial formula
P(x=1) = nCx P^x q ^ n-x
= 12C1 (0.15)^1 (0.85)^ 12-1
= 12 × 0.15 × (0.85)^11
= 0.3012
See attached picture
