Answer:
[tex]8\frac{1}{8}[/tex] ounces.
Step-by-step explanation:
Given
Number of rows of corn [tex]=2\frac{1}{2}[/tex] rows.
Seed required in each row is [tex]=3\frac{1}{4}[/tex] ounces.
So, total seed required to plant corn in [tex]2\frac{1}{2}[/tex] rows is
Number of rows of corn [tex]\times[/tex] Seed required in each row
[tex]=(2\frac{1}{2})\times(3\frac{1}{4})\\\\\ Multply\ denominator\ to\ whole\ number\ part\ then\ add\ that\ number\ to\ numerator\\\\=\frac{5}{2}\times\frac{13}{4}\\ \\Divide\ 65\ by\ 8\ we\ have\ 8\ with\ reminder\ 1\\\\=\frac{65}{8}\\\\So,\frac{65}{8} =8\frac{1}{8}[/tex]