Answer:
[tex]\frac{1}{x^2}[/tex]
Step-by-step explanation:
Differentiate using the power rule
[tex]\frac{d}{dx}[/tex](a[tex]x^{n}[/tex]) = na[tex]x^{n-1}[/tex]
Given
f(x) = - [tex]\frac{1}{x}[/tex] = - [tex]x^{-1}[/tex], then
f'(x) = - 1 × - 1 × [tex]x^{-1-1}[/tex] = [tex]x^{-2}[/tex] = [tex]\frac{1}{x^2}[/tex]
