Answer:
A sample of at least 68 bulbs is needed to be 96% confident that our sample mean will be within 10 hours of the true mean.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1-0.96}{2} = 0.02[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].
So it is z with a pvalue of [tex]1-0.02 = 0.98[/tex], so [tex]z = 2.055[/tex]
Now, find the margin M as such
[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
In this problem, we have that:
[tex]\sigma = 40, M = 10[/tex]
[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]
[tex]10 = 2.055*\frac{40}{\sqrt{n}}[/tex]
[tex]10\sqrt{n} = 82.2[/tex]
[tex]\sqrt{n} = 8.22[/tex]
[tex]n = 67.6[/tex]
A sample of at least 68 bulbs is needed to be 96% confident that our sample mean will be within 10 hours of the true mean.