Answer:
C
Step-by-step explanation:
Consider all options:
A. [tex]\sqrt{2}[/tex] is irrational number because it cannot be represented as a fraction with integer numerator and natural denominator. This option is false.
B. Number 0 is integer number, therefore, its rational number. This option is false.
C. Repeating decimal [tex]1.\overline{3}[/tex] can be represented as [tex]1 \dfrac{1}{3}[/tex] that is [tex]\dfrac{4}{3}[/tex] and, therefore, this number is rational number. This number is not integer number, because this is a fraction when simplified to lowest terms. So, this option is true.
D. Number [tex]-\sqrt{16}=-4[/tex] and is integer, therefore, is rational number. So, this option is false.
