Answer:
[tex]3.849 m^{3}[/tex]
Explanation:
Assuming that helium behaves as an ideal gas and taking gas constant of helium as
R=2.0769 kJ/KgK
From ideal gas equation
PV=mRT and making V the subject then
[tex]V=\frac {mRT}{P}[/tex]
Where m is the mass, V is the volume, P is pressure, T is temperature in Kelvin
Substituting the figures given in the question then
[tex]V=\frac {2\times 2.0769\times 278}{300}=3.849188
\approx 3.849 m^{3}[/tex]
Therefore, volume of container is [tex]3.849 m^{3}[/tex]
