Respuesta :
Answer:
[tex]m\angle QOB=75^o[/tex]
[tex]m\angle QBO=15^o[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
Find the measure of angle ∠QBO
we know that
The incenter of a triangle is the intersection of its interior angle bisectors
so
[tex]m\angle QBO=m\angle OBR[/tex]
we have
[tex]m\angle OBR=15^o[/tex] ---> given problem
so
[tex]m\angle QBO=15^o[/tex]
step 2
Find the measure of angle ∠QOB
we know that
In the right triangle QOB
[tex]m\angle QOB+m\angle QBO=90^o[/tex] ---> by complementary angles
we have
[tex]m\angle QBO=15^o[/tex]
substitute
[tex]m\angle QOB+15^o=90^o[/tex]
[tex]m\angle QOB=90^o-15^o[/tex]
[tex]m\angle QOB=75^o[/tex]
