Respuesta :

Answer:

[tex]m\angle QOB=75^o[/tex]

[tex]m\angle QBO=15^o[/tex]

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle ∠QBO

we know that

The incenter of a triangle is the intersection of its interior angle bisectors

so

[tex]m\angle QBO=m\angle OBR[/tex]  

we have

[tex]m\angle OBR=15^o[/tex] ---> given problem

so

[tex]m\angle QBO=15^o[/tex]

step 2  

Find the measure of angle ∠QOB

we know that

In the right triangle QOB

[tex]m\angle QOB+m\angle QBO=90^o[/tex] ---> by complementary angles

we have

[tex]m\angle QBO=15^o[/tex]

substitute

[tex]m\angle QOB+15^o=90^o[/tex]

[tex]m\angle QOB=90^o-15^o[/tex]

[tex]m\angle QOB=75^o[/tex]

Ver imagen calculista

The answer is 12.

Trust me

ACCESS MORE
EDU ACCESS