Respuesta :
Answer: 1. 11.04moles
2. 33.6L
Explanation:Please see attachment for explanation

Answer:
For 1: The number of moles of ethanol are 11.04 moles
For 2: The volume of chlorine gas at STP for given amount is 33.6 L
Explanation:
- For 1:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of ethanol = 508 g
Molar mass of ethanol = 46 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of ethanol}=\frac{508g}{46g/mol}=11.04mol[/tex]
Hence, the number of moles of ethanol are 11.04 moles
- For 2:
We are given:
Moles of chlorine gas = 1.50 moles
At STP:
1 mole of a gas occupies 22.4 L of volume
So, 1.50 moles of chlorine gas will occupy = [tex]\frac{22.4}{1}\times 1.50=33.6L[/tex] of volume
Hence, the volume of chlorine gas at STP for given amount is 33.6 L
