Respuesta :

r3t40

[tex]

\displaystyle

n+1=4(n-8) \\

n+1=4n-32 \\

-3n+33=0 \\

-3(n-11)=0 \\

n-11=0 \\

n=11

[/tex]

Hope this helps.

Answer:n=11

Step-by-step explanation:n+1=4n-32

3n-n=-32-1

N=11

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