Question

. Gravitational force of attraction "F" exists between two-point masses A and B when a fixed distance separates them. After mass A is doubled and mass B is quartered, the gravitational attraction between the two masses is___________.

Answer 1

Answer:8F

Explanation:

Given

Gravitation attraction is F between A and B

if $m_a$ and $m_b$ is the mass of A and B respectively then

F is given by

$F=\frac{Gm_am_b}{r^2}$

where r=distance between them

if $m_a$ is doubled and $m_b$ is quadrupled then Force can be given by

$F'=\frac{G\times 2m_a\times 4m_b}{r^2}$

$F'=\frac{8Gm_am_b}{r^2}$

$F'=8F$

thus force becomes 8 times of initial value

Answer 2

Answer:

0.5F OR HALF OF PREVIOUS VALUE

Explanation:

F= G Ma Mb/r²

now new force F1 is given as

F1= G ×2Ma × 0.25 Mb /r²

F1 = 2×0.25 ×Ma×Mb/r²

F1 = 0.5×Ma Mb/r²

F1= 0.5 F