in this problem, there is only one intersection point, because the problem above is two straight lines.
example problems above :
has two straight lines namely
y = 4x + 1...........(first equation)
and
y = -2x + 4............(second equation)
look for the x value first
y1 = y2
4x + 1 = -2x + 4
6x = 3
x = ½
then find the value of y by entering the first equation
y = 4x + 1
y = 4(½) + 1
y = 2 + 1
y = 3
Finally, the intended intersection point is (½,3)