Answer:
179.7 N
Explanation:
Notice: check attached file/picture for the diagram showing the arrangement of charged particles.
The mathematical expression for coulumb's law is given below;
F= Kq1q2/ r^2 ---------------------------(1).
Slotting in the given parameters;
F(1)= 8.9875× 10^9 × 3× 6/(0.12)^2.
F(1)= 161,775,000,000/ 0.144.
F(1)= 11,234,375,000,000
F(1)= 11.2 N towards left.
Also, the force due to -5 uC charge placed at x = 6 cm.
Using coulumb's law equation in equation (1), we have;
F(2)= 8.9875×10^9 × 5 × 6/ (0.042).
F(2)= 168.5 N.
Therefore, net force on 6 uC charge will be;
=F(1)+ F(2)
= 168.5 N + 11.2 N
= 179.7N.
Hence, the magnitude of the total electrostatic force on a third particle with charge 6 is 179.7 N
