Answer:
0.52474, 0.47526
Step-by-step explanation:
given that based in the U.S. Census Bureau’s American Community Survey of 2017, 12.9% of the U.S. population was foreign-born.
The U.S. Census Bureau uses the term foreign-born to refer to anyone who is not a U.S. citizen at birth.
Hence for a randomly selected citizen to be foreign born has constant probability 12.9% since each person is independent of the other and there are only two outcomes.
For the sample of 5 students, X = foreign born is binomial (5, 0.129)
1) the probability that none of the students are foreign-born (x=0)
=[tex](1-0.129)^5\\= 0.52474[/tex]
2 p(x>=1) (that at least one is foreign-born)
= [tex]1-P(0)\\=1-0.52474\\= 0.47526[/tex]