Answer:
1.608
Explanation:
According to Graham's effusion law, the rate of effusion (r) of a gas in inversely proportional to the root square of its molar mass (M). The ratio rNH₃ to rCO₂ is:
[tex]\frac{r_{NH_{3}}}{r_{CO_{2}}} =\sqrt{\frac{M(CO_{2})}{M(NH_{3})}} =\sqrt{\frac{44.01g/mol}{17.03g/mol} } =1.608[/tex]
If CO₂ and NH₃ are allowed to effuse through a porous membrane under identical conditions, the rate of effusion for NH₃ will be 1.608 times that of CO₂.