Answer:
1029 Jkg⁻¹
Explanation:
[tex]h[/tex] = height dropped by the water falling = 105 m
[tex]g[/tex] = acceleration due to gravity = 9.8 ms⁻²
[tex]m[/tex] = mass of water
Using conservation of energy, the internal energy produced is same as the gravitational potential energy lost, hence
Internal energy = Gravitational potential energy
[tex]U = mgh \\\frac{U}{m} = gh\\\frac{U}{m} = (9.8) (105)\\\frac{U}{m} = 1029 Jkg^{-1}[/tex]