Answer:
option C
Explanation:
given,
Range is doubled
for range to be doubled height should become 4 times.
formula to calculate the horizontal range
R = v T_{flight}
using equation of motion
[tex]s = u t + \dfrac{1}{2}at^2[/tex]
[tex]t=\sqrt{\dfrac{2s}{g}}[/tex]
now,
[tex]R = v\sqrt{\dfrac{2h}{g}}[/tex]
where, h is the height of the
Assuming the height be equal to 0.6 m
to calculate the new height
[tex]h_{new}= 4 h[/tex]
[tex]h_{new}= 4\times 0.6[/tex]
[tex]h_{new}= 2.4\ m[/tex]
hence, the correct answer is option C