Answer:
F=1.65 x 10²⁶ N
Explanation:
Given that
Distance ,R= 3.34 x 10¹² m
Mass m₁= 2.78 x 10³⁰ kg
Mass ,m₂= 9.94 x 10³⁰ kg
we know that gravitational force F given as
[tex]F=G\dfrac{m_1m_2}{R^2}[/tex]
G=Constant
G=6.67 x 10⁻¹¹ Nm²/kg²
Now by putting the values
[tex]F=6.67\times 10^{-11}\times \dfrac{2.78\times 10^{30}\times 9.94\times 10^{30}}{(3.34\times 10^{12})^2}\ N[/tex]
F=1.65 x 10²⁶ N
Therefore the force between these two mass will be 1.65 x 10²⁶ N.