Answer:
EV of node 4 = 0.6×5 + 0.4×0 = 3
EV of node 5 = 0.1×5 + 0.9×0 = 0.5
EV of node 2 = (0.8×5 + 0.2×EV of node 4) - 3
EV of node 2 = (0.8×5 + 0.2×3 ) - 3
EV of node 2 = 4.6 - 3
EV of node 2 = 1.6
EV of node 3 = (0.5×5 + 0.5×EV of node 5) - 1
EV of node 3 = (0.5×5 + 0.5×0.5 ) - 1
EV of node 3 = 2.75 - 1
EV of node 3 = 1.75
EV of node 3 is higher, therefore, best attend pattern is to attend randomly.