Question

A 50.0-kg crate is being pulled along a horizontal smooth surface. The pulling force is 10.0 N and is directed 20.0° above the horizontal. What is the magnitude of the acceleration of the crate?a. 250 N, 0.0684 m/s²
b. 487 N, 0.188 m/s²
c. 525 N, 0.200 m/s²
d. 825 N, 0.376 m/s²
e. 494 N, 0.0728 m/s²

Answer 1

Answer:$b-0.188 m/s^2$

Explanation:

Given

mass of crate $m=50 kg$

Magnitude of friction $F=10 N$

Inclination of Force $\theta =20^{\circ}$

Force cos component will move the Block

$F_{net}=F\cos \theta =ma$

$a=\frac{10\cos 20}{50}$

$a=0.188 m/s^2$