Answer:D
Explanation:
Given
Force required to move a box at steady rate is F=78 N
Weight of Block W=150 N
If the block is moving at a steady rate then net Force acting on it is zero
Applied Force must balance the Friction force
[tex]F=f_r[/tex]
[tex]f_r=\mu N[/tex]
where N=normal Reaction
Normal reaction must be equal to weight
[tex]\mu \times 150=78[/tex]
[tex]\mu =0.52[/tex]