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Two horizontal forces are exerted on a large crate. The first force is 317 N to the right. The second force is 173 N to the left a. Draw a force diagram for the horizontal forces acting on the crate. b. What is the net force acting on the crate? c. The box is initially at rest. Five seconds later, its velocity is 6.5 m/s to the right. What is the crate's mass?

Respuesta :

Answer:

A. Refer to the figure.

B. The net force acting on the crate is

[tex]F_{net} = F_1 - F_2 = 317 - 173 = 144N[/tex]

C. We should first find the acceleration of the crate using the following kinematics equation:

[tex]v = v_0 + at\\6.5 = 0 + 5a\\a = 1.3 m/s^2[/tex]

Mass of the crate can be found by Newton’s Second Law:

[tex]F = Ma\\M = F/a = 144/1.3 = 110.7 kg[/tex]

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