Answer:
a) [tex]\pm 8\frac{x^{5}}{5}+C[/tex]
b) [tex]\pm 4 sin(2x) + C[/tex]
Step-by-step explanation:
Given integrals are:
[tex]a) \int\limits^a_b {\sqrt{{1+64x^{8}} } \, dx [/tex] ---(1)
[tex]b) \int\limits^a_b {\sqrt{1+64cos^{2}(2x)} } \, dx[/tex]---- (2)
Standard form
[tex]L= \int\limits^a_b {\sqrt{1+(f'(x))^{2}} } \, dx[/tex]
compare (1) with standard form
[tex][f'(x)]^{2} = 64x^{8}\\f'(x)=\pm 8x^{4}\\f(x)= \pm8\frac{x^{5}}{5}+C[/tex]
Compare (2) with standard form
[tex][f'(x)]^{2}=64cos^{2}(2x)\\f'(x)= \pm 8cos(2x)\\f(x)=\pm 8\frac{sin(2x)}{2}+C\\f(x)= \pm 4sin(2x)+C[/tex]