Answer:
12.0 mL
Explanation:
AlBr₃ is a strong electrolyte that ionizes according to the following equation.
AlBr₃(aq) → Al³⁺(aq) + 3 Br⁻(aq)
If the concentration of AlBr₃ is 0.580 M, the concentration of Br⁻ is 3 × 0.580 M = 1.74 M.
This is the initial concentration C₁. We want to prepare a diluted solution with C₂ = 0.233 M and V₂ = 89.3 mL. To find out V₁, we will use the dilution rule.
C₁ × V₁ = C₂ × V₂
1.74 M × V₁ = 0.233 M × 89.3 mL
V₁ = 12.0 mL
Answer:
The initial volume is 35, 9 ml
Explanation:
We use the formula:
V initial x C Initial = V Final x C Final , being V = volume and C = concentration
V initial x 0, 580 M = 89, 3 ml x 0, 233 M
V initial = (89, 3 ml x 0, 233 M)/0, 580 M = 35, 9 ml
