Question

Please Help....

P(1, 0) corresponds to
(, ) on the cosine graph.
P(0, 1) corresponds to
(, ) on the cosine graph.
P(−1, 0) corresponds to
(, ) on the cosine graph.
P(0, −1) corresponds to
(, ) on the cosine graph.

Answer 1

You can use the angles that those points make with positive x axis to evaluate cosine of that angle. The obtained cosine value will be the y ordinate on cosine graph and the angle will be x abscissa on the cosine graph.

The answers are:

• P(1, 0) corresponds to (0,1) on the cosine graph.
• P(0,1) corresponds to (90,0) on the cosine graph.
• P(-1,0) corresponds to (180, -1) on the cosine graph.
• P(0,-1) corresponds to (270, 0) on the cosine graph.

How to evaluate points on the cosine graph?

We already know that

• P tracking points of unit circle.

• $y = cos(\theta)$plotting cosine graph for each angle P makes with the initial line on positive x-axis.

We can evaluate the angle those points make with the positive x axis and then feed that angle to cos function to get the output.

• On P(1,0):

The angle is 0 degrees:

Thus, $y = cos(0) = 1$

Thus point on cosine graph is   $(\theta, y) = (0,1)$

• On P(0,1):

The angle is 90 degrees:

Thus, $y = cos(90) = 0$

Thus point on cosine graph is   $(\theta, y) = (90,0)$

• On P(-1,0):

The angle is 180 degrees:

Thus, $y = cos(180) = -1$

Thus point on cosine graph is   $(\theta, y) = (180,-1)$

• On P(0,-1):

The angle is 270 degrees:

Thus, $y = cos(270) = 0$

Thus point on cosine graph is   $(\theta, y) = (270,0)$

Thus, we get:

• P(1, 0) corresponds to (0,1) on the cosine graph.
• P(0,1) corresponds to (90,0) on the cosine graph.
• P(-1,0) corresponds to (180, -1) on the cosine graph.
• P(0,-1) corresponds to (270, 0) on the cosine graph.

Learn more about cosine graph here:

https://brainly.com/question/14290164

Answer 2

Answer:

(0,1)

(90,0)

(180, -1)

(270, 0)

Step-by-step explanation: