Question

The angle of refraction rounded to the nearest whole number
An incident light ray strikes water at an angle of 20 degrees.
The index of refraction of air is 1.0003, and the index of
refraction of water is 1.33.
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Answer 1

Answer:

$15^{\circ}$

Explanation:

Using Snell's law which is represented by

$n_1sin\theta_1 = n_2sin\theta_2$

Making $\theta_2$ the subject of the formula then

$\theta_2=sin^{-1}(\frac {n_1sin\theta_1}{n_2})$

Here $\theta_1$ and $\theta_2$ are the angles of incidence and refraction in water and air respectively

$n_1$ and $n_2$ are refraction index

Substituting 1.0003 for $n_1$ and 1.33 for $n_2$ then $20^{\circ}$ for $\theta 1$ we obtain

$\theta_2=sin^{-1}(\frac {1.0003\times sin 20^{\circ}}{1.33})=14.90606875^{\circ}\approx 15^{\circ}$

Answer 2

Answer:

B on Edge or 17°

Explanation: