Answer:
SCl₂
Explanation:
In order to know the empirical formula, we have to follow a series of steps.
Step 1: Divide each percentage by the atomic mass
S: 26.95/32.07 = 0.8403
Cl: 59.61/35.45 = 1.682
Step 2: Divide all the numbers by the smallest one.
S: 0.8403/0.8403 = 1
Cl: 1.682/0.8403 ≈ 2
The empirical formula of the compound is SCl₂.
Answer:
The empirical formula = the simplest formula of this compound is SOCl2
Explanation:
Step 1: Data given
Suppose the mass of the compound is 100 grams
The compound contains:
⇒ 26.95 % sulfur = 26.95 grams
⇒ 59.61 % chlorine = 59.61 grams
⇒ 100 - 26.95 - 59.61 = 13.44 % oxygen = 13.44 grams
Molar mass of sulfur = 32.065 g/mol
Molar mass of oxygen = 16 g/mol
Molar mass of chlorine = 35.45 g/mol
Step 2: Calculate moles
Moles = mass / molar mass
Moles Sulfur = 26.95 grams / 32.065 g/mol = 0.8405 moles
Moles chlorine = 59.61 grams / 35.45 g/mol = 1.682 moles
Moles oxygen = 13.44 grams / 16 g/mol = 0.84 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
S: 0.8405/0.84 = 1
Cl = 1.682 / 0.84 = 2
O = 0.84 / 0.84 = 1
The empirical formula = the simplest formula of this compound is SOCl2
