Respuesta :

r3t40

Well if so then

[tex]

3\mid(22n+1+7)\wedge n>1 \\

3\mid2(11n+4)\wedge n>1 \\

[/tex]

Which is false since [tex]3\mid2[/tex] is false. However we have [tex]3\mid2x[/tex] is true if [tex]x\mid3[/tex] or in this case [tex]11n+4\mid3[/tex].

So it's true in some cases false.

Hope this helps.

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