An object when orbiting the Earth at a height of three Earth radii from the center of the Earth has a weight of 1.00 N. What is the object’s mass? (g at the surface of the Earth is 9.8 m/s^2)

Respuesta :

Answer:0.918 kg

Explanation:

Given

Object is at a distance of r=3 R from earth surface

where R=radius of Earth

acceleration due to Gravity is given by

[tex]g=\frac{Gm_e}{R^2}[/tex]

at earth surface [tex]g=9.8 m/s^2[/tex]

g at [tex]r=3 R[/tex]

[tex]g'=\frac{Gm_e}{(3R)^2}[/tex]

[tex]g'=\frac{Gm_e}{9R^2}[/tex]

[tex]g'=\frac{g}{9}[/tex]

Weight at r=3R is 1 N

thus Weight at Earth surface will be 9 times at r=3R

weight at  Earth surface =9 N

[tex]mass=\frac{9}{9.8}=0.918 kg[/tex]

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