Question

Graph the linear inequality: 2x + 3y = 12, by creating a t-chart to plot the points. Shade by
testing a point and show all of your work

Answer 1

Answer:

See explanation

Step-by-step explanation:

Assuming the given inequality is $2x+3y\le12$

Then the corresponding linear equation is $2x+3y=12$

When x=0, we have  $2*0+3y=12$

$\implies 3y=12\implies y=4$

When y=0, we have  $2x+3*0=12$

$\implies 2x=12\implies x=6$

The T-table is:

x   |   y

0   |   4

6   |   12

We plot this points and draw a solid straight line as shown in the attachment.

Now let us test the origin: (0,0) by plugging x=0 and y=0 into the inequality.

$2*0+3*0\le12$

$0\le12$....This is true so we shade the lower half plane as shown in the attachment.